Consider the line $\vec r=\hat i-2\hat j+4\hat k+λ(-\hat i+2\hat j-4\hat k)$ Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) |
(A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Given line $\vec r=\hat i-2\hat j+4\hat k+\lambda(-\hat i+2\hat j-4\hat k)$ A point on the line is obtained by taking $\lambda=0$ Point $=(1,-2,4)$ $(A)\rightarrow(III)$ Direction vector of the line $\vec d=(-1,2,-4)$ Hence direction ratios are $(-1,2,-4)$ $(B)\rightarrow(IV)$ Magnitude of direction vector $|\vec d|=\sqrt{(-1)^2+2^2+(-4)^2}=\sqrt{21}$ Direction cosines $\left(\frac{-1}{\sqrt{21}},\frac{2}{\sqrt{21}},\frac{-4}{\sqrt{21}}\right)$ $(C)\rightarrow(I)$ A line perpendicular to the given line must have direction ratios proportional to $(4,-2,-2)$ since $(-1,2,-4)\cdot(4,-2,-2)=-4-4+8=0$ $(D)\rightarrow(II)$ Final Matching: (A)-(III), (B)-(IV), (C)-(I), (D)-(II). |