A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance $s_1$ in 10 sec and distance $s_2$ in the next 10 sec, then
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $s_1 = \frac{s_2}{3}$
$s_1 = \frac{1}{2}a(10)^2$
and $s=\frac{1}{2}a(20)^2=4s_1$
or $s_2 = s – s_1 = 3s_1$
$∴s_1 = \frac{s_2}{3}$