A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance $s_1$ in 10 sec and distance $s_2$ in the next 10 sec, then

$s_1 = s_2$ $s_1 = \frac{s_2}{3}$ $s_1 = \frac{s_2}{2}$ $s_1 = \frac{s_2}{4}$

$s_1 = \frac{s_2}{3}$

The correct answer is Option (2) → $s_1 = \frac{s_2}{3}$ $s_1 = \frac{1}{2}a(10)^2$ and $s=\frac{1}{2}a(20)^2=4s_1$ or $s_2 = s – s_1 = 3s_1$ $∴s_1 = \frac{s_2}{3}$