If tan (5α - 35°) = cot (35° - 2α) then the value of  sin 2α .

0  \(\frac{\sqrt {3}}{2}\)  1  \(\frac{\sqrt {5}}{2}\)

\(\frac{\sqrt {3}}{2}\)

[Concept: tan A = cot B, when A + B = 90°] Therefore, (5a - 35° + 35° - 2α) = 90° 3α = 90° α = 30° Put this value in find → ⇒  sin 2α ⇒  sin60° =  \(\frac{\sqrt {3}}{2}\)