If tan (5α - 35°) = cot (35° - 2α) then the value of sin 2α . |
0 \(\frac{\sqrt {3}}{2}\) 1 \(\frac{\sqrt {5}}{2}\) |
\(\frac{\sqrt {3}}{2}\) |
[Concept: tan A = cot B, when A + B = 90°] Therefore, (5a - 35° + 35° - 2α) = 90° 3α = 90° α = 30° Put this value in find → ⇒ sin 2α ⇒ sin60° = \(\frac{\sqrt {3}}{2}\) |