The frequency of incident light falling on a photo sensitive plate is doubled, then maximum kinetic energy of the emitted photoelectrons will become –

2 times of the earlier value More than 2 times of the earlier value Less than 2 times of the earlier value Unchanged

More than 2 times of the earlier value

$KE_{max}=h(v-v_0)$ $\frac{KE_{max}}{KE_{max}}=\frac{h(2v-v_0)}{h(v-v_0)}>2$