If a + \(\frac{1}{a + 4}\) = 5 Then find , (a + 4)3 + \(\frac{1}{(a + 4)^3}\)

729 730 702 700

702

Given = a + \(\frac{1}{a + 4}\) = 5 By adding 4 on both sides we get, (a + 4) + \(\frac{1}{a + 4}\) = 5 + 4 = 9 (a + 4)3 + \(\frac{1}{(a + 4)^3}\) = 93 - 3 × 9 = 702   Note - if x +  \(\frac{1}{x}\) = a then x3 + \(\frac{1}{x^3}\) =  a3 - 3a