The ratio of speeds of two aeroplanes is 11 : 18. If the first aeroplane covers a distance of 1650 km in 3 hours, then what is the speed (in m/s) of the second aeroplane?
Answer & explanation
Correct answer: option 4
Ratio of speed of Aeroplanes is 11 : 18
We know, Speed = \(\frac{Distance}{Time}\)
Hence, the speed of the first aeroplane = \(\frac{1650}{3}\)
= 550 km/hour
According to question ,
Now, 11R = 550
R = 50
Hence, the speed of the second aeroplane = 18R = 18 × 50 = 900 km/h
= 900 × \(\frac{5}{18}\) = 250 m/sec
So , The speed of the second aeroplane is 250 m/sec.