In a ΔABC, the bisector of&nb

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 2D

Question:

In a ΔABC, the bisector of ∠A meets BC at D. If AB = 9.6 cm, AC = 11.2 cm and BD = 4.8 cm, the perimeter (in cm) of ΔABC is :

Options:

30.4

28.6

31.2

32.8

Correct Answer:

31.2

Explanation:

\(\frac{AB}{CD}\) = \(\frac{AB}{AC}\)

\(\frac{4.8}{CD}\)= \(\frac{9.6}{11.2}\)

= CD = 5.6

So,

BC = 4.8 + 5.6 = 10.4

Now,

Perimeter of ΔABC = 9.6 + 10.4 + 11.2 = 31.2 cm