CUET Preparation Today
What is the derivative of $f(x)=2\sqrt{\cos(x^2)}$ |
$\frac{-2\sin(x^2)}{\cot(x^2)}$ $\frac{-2x\sin(x^2)}{\sqrt{\cos(x^2)}}$ $\tan^2x$ $\sin^2x$ |
$\frac{-2x\sin(x^2)}{\sqrt{\cos(x^2)}}$ |
$f(x)=2\sqrt{\cos(x^2)}$ so $f'(x)=\frac{-2x\sin(x^2)}{\sqrt{\cos(x^2)}}$ |
