What is the derivative of $f(x)=2\sqrt{\cos(x^2)}$
Answer & explanation
Correct answer: option 2
$f(x)=2\sqrt{\cos(x^2)}$
so $f'(x)=\frac{-2x\sin(x^2)}{\sqrt{\cos(x^2)}}$
What is the derivative of $f(x)=2\sqrt{\cos(x^2)}$
Correct answer: option 2
$f(x)=2\sqrt{\cos(x^2)}$
so $f'(x)=\frac{-2x\sin(x^2)}{\sqrt{\cos(x^2)}}$