The area of the region bounded by the curves $x^2=4y$, the line $x=3$ and x-axis is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{9}{4}$
$x^2=4y,x=3$
so required area → $\int\limits_0^3\frac{x^2}{4}dx$
$=\left[\frac{x^3}{12}\right]_0^3=\frac{9}{4}$ sq. units
