Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

What is the power factor of an ac circuit having resistance R and Inductance L connected in series? (ω is the angular frequency)

Options:

$(ωL)R^{-1}$

$R(ωL)^{-1}$

$R/(R^2-ω^2L^2)^{-\frac{1}{2}}$

$R/(R^2+ω^2L^2)^{-\frac{1}{2}}$

Correct Answer:

$R/(R^2+ω^2L^2)^{-\frac{1}{2}}$

Explanation:

Power Factor is $cos\phi = \frac{R}{Z} = \frac{R}{\sqrt{R^2+\omega^2L^2}}$

The correct answer is Option (4) → $R(R^2+ω^2L^2)^{-\frac{1}{2}}$