If A and B are matrices of same order, then $(AB^T - BA^T)$ is always |
a symmetric matrix a skew symmetric matrix neither a symmetric matrix nor a skew-symmetric matrix a null matrix |
a skew symmetric matrix |
The correct answer is Option (2) → a skew symmetric matrix Given expression $AB^T-BA^T$ Take transpose $(AB^T-BA^T)^T=(AB^T)^T-(BA^T)^T$ $=BA^T-AB^T$ $=-(AB^T-BA^T)$ Hence $(AB^T-BA^T)^T=-(AB^T-BA^T)$ This shows the matrix is skew-symmetric The given expression is always a skew-symmetric matrix. |