In $ΔABC$, points D and E are on AB and AC respectively such that $DB=16\, cm , AE =24 \, cm$ and $EC=12\, cm$. If $AB=48\, cm, ∠DAE=95°$ and $∠ADE=42°$, then find $∠ACB.$

$43°$

We know that if the ratio of AD and DB is 2 : 1 then the angle ADE and ABC are equal.

So, angle ABE = 43^o

So in triangle ABC the sum of the all internal angles is 180o

So we have two angles then the third angle will be = 180 - 95 - 42 = 43^o

The correct answer is option (2) : $43°$