Target Exam

CUET

Subject

Biology

Chapter

Molecular Basis of Inheritance

Question:

Match List - I with List - II.

List – I

List – II

(A) Operator

(I) RNA polymerase

(B) Promotor

(II) Permeability of the cell

(C) y-gene

(III) Hydrolysis of a specific disaccharide

(D) z-gene

(IV) Repressor protein

Choose the correct answer from the options given below:

Options:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Correct Answer:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Explanation:

The correct answer is Option (1) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

List – I

List – II

(A) Operator

(IV) Repressor protein

(B) Promotor

(I) RNA polymerase

(C) y-gene

(II) Permeability of the cell

(D) z-gene

(III) Hydrolysis of a specific disaccharide

The lac operon consists of one regulatory gene (the i gene – here the term i does not refer to inducer, rather it is derived from the word inhibitor) and three structural genes (z, y, and a). The i gene codes for the repressor of the lac operon. The z gene codes for beta-galactosidase ( β-gal), which is primarily responsible for the hydrolysis of the disaccharide, lactose into its monomeric units, galactose and glucose. The y gene codes for permease, which increases permeability of the cell to β-galactosides. The a gene encodes a transacetylase. Hence, all the three gene products in lac operon are required for metabolism of lactose.

The repressor of the operon is synthesised (all-the-time – constitutively) from the i gene. The repressor protein binds to the operator region of the operon and prevents RNA polymerase from transcribing the operon. In the presence of an inducer, such as lactose or allolactose, the repressor is inactivated by interaction with the inducer. This allows RNA polymerase access to the promoter and transcription proceeds.