Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

In the circuit shown below, $C_1 = 6 μF, C_2 = 3 μF$ and battery $B = 40 V$. Initially, switch $A_1$ is opened and the switch $A_2$ is closed. Now switch $A_2$ is opened and $A_1$ is closed. The charge on $C_2$ will be

Options:

100 μC

40 μC

80 μC

18 μC

Correct Answer:

80 μC

Explanation:

The correct answer is Option (3) → 80 μC