CUET Preparation Today
The figure given below shows two parallel equipotential surfaces A and B kept a small distance r apart from each other. A point charge of q couloub is taken from the surface A to B. The amount of net work W done will be |
$ W = - \frac{q}{4\pi \epsilon_0 r}$ $ W = - \frac{q}{4\pi \epsilon_0 r^2}$ $ W = \frac{q}{4\pi \epsilon_0 r^2}$ Zero |
Zero |
$W = q\Delta V = q (0) = 0$ |
