Rolle's theorem holds for the function $x^3+b x^2+c x, 1 \leq x \leq 2$ at the point $\frac{4}{3}$, the value of b and c are
Answer & explanation
Correct answer: option 4
f'(4/3) = 0
⇒ 16 + 8b + 3c = 0
Also f(1) = f(2)
⇒ 3b + c + 7 = 0
Hence b = –5, c = –8