A man and his wife appear in an interview. The probability of husband‘s selection is \(\frac{1}{3}\)and the probability of wife‘s selection is \(\frac{2}{5}\) .What is the probability that only one of them is selected?
Answer & explanation
Correct answer: option 2
Probability of man‘s selection is = \(\frac{1}{3}\)
Probability of wife ‘s selection is = \(\frac{2}{5}\)
Probability that any one of them is selected = probability of man‘s selection and not wife selection or probability of wife‘s selection not man
Then probability = \(\frac{1}{3}\) × ( 1- \(\frac{2}{5}\) ) + \(\frac{2}{5}\) × ( 1- \(\frac{1}{3}\) )
= \(\frac{7}{15}\)