If A, B, C be three sets such that $A∪B=A∪C$ and $A∩B=A∩C$, then |
$A =B$ $B=C$ $A=C$ $A=B=C$ |
$B=C$ |
We have, $A∪B=A∪C$ $⇒(A∪B)∩C=(A∪C)∩C$ $⇒(A∩C)∪(B∩C)=C$ $⇒(A∩B)∪(B∩C)=C$ $[∵A∩C=A∩B]$ ..(i) Again, $A∪B=A∪C$ $⇒(A∪B)∩B=(A∪C)∩B$ $⇒B=(A∩B)∪(B∩C)$ ...(ii) From (i) and (ii), we get $B = C$. |