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If $7 \sin^2 \theta + 3 \cos^2 \theta = 4, 0^\circ < \theta < 90^\circ$, then the value of tanθ is: |
7 $\frac{1}{√3}$ $\frac{15}{4}$ $\frac{13}{4}$ |
$\frac{1}{√3}$ |
7 sin²θ + 3 cos²θ = 4 4 sin²θ + 3 sin²θ + 3 cos²θ = 4 { using , sin²θ + cos²θ = 1 } \ 4 sin²θ + 3 = 4 Sinθ = \(\frac{ 1}{2}\) { using , Sin30º = \(\frac{ √3}{2}\) } So, θ = 30º tanθ = tan30º = \(\frac{ 1}{√3}\)
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