If (4≤ft[(17)^3-(7)^3])/(≤ft(17^2+7^2+p))=40, then what is the value…

( a - b ) = \(\frac{a^3 - b^3}{a^2 + b^2 + ab }\)

$\frac{4\left[(17)^3-(7)^3\right]}{\left(17^2+7^2+p\right)}=40$

By comparing the values from both of the equation we get = 

a = 17

b = 9

p = ab = 17 × 9 =  119