Magnetic moment of Fex+ ion is \(\sqrt{35}\) B.M.What is the number of unpaired electrons?
Answer & explanation
Correct answer: option 1
Magnetic moment is given by, u = \(\sqrt {n(n+2) }\)
\(\sqrt {35}\) = \(\sqrt {n(n+2) }\)
n = 5 (Unpaired electrons)
Fe is present in +3 oxidation state i.e. [Ar]3d5 configuration.