Two fair and ordinary dice are rolled simultaneously. The probability of getting the sum of outcomes of the dice as a multiple of 4, is equal to
Answer & explanation
Correct answer: option 2
In the case sum can be 4 or 8 or 12.
Total ways of getting the sum as 4
= 3 (namely (2, 2), (1, 3), (3, 1)).
Total ways of getting the sum as 8
= 5 (namely (2, 6), (6, 2), (3, 5), (5, 3), (4, 4))
Total ways of getting the sum as 12
= 1 (namely (6, 6))
Thus total ways of getting the sum as multiple of four
= 3 + 5 + 1 = 9
Thus, required probability = $\frac{9}{36}=\frac{1}{4}$