The number of electric lines of force originating from a charge of 1 C is |
$11.29 × 10^{16}$ $1.129 × 10^{8}$ $1.129 × 10^{11}$ $1.129 × 10^{15}$ |
$1.129 × 10^{11}$ |
The correct answer is Option (3) → $1.129 × 10^{11}$ The number of electric lines of force originating from a charge $q$ is proportional to the magnitude of the charge: $N = \frac{q}{\varepsilon_0}$ Given $q = 1 \, \text{C}$, $\varepsilon_0 = 8.854 \times 10^{-12} \, \text{C}^2/\text{N·m}^2$ $N = \frac{1}{8.854 \times 10^{-12}} \approx 1.13 \times 10^{11}$ Number of lines of force ≈ 1.13 × 10¹¹ |