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Find the area common to the parabola x = -2y2 and x = 1 - 3y2. |
8/3 16/3 4/3 20/3 |
4/3 |
Required Area = 2 × shaded area = $2\int\limits_0^A[(1-3y^2)-(-2y^2)]dy$
Solve x = -2y2 & x = 1 - 3y2 ⇒ A ≡ (-2, 1) ⇒ Required Area = $2\int\limits_0^1(1-y^2)dy=4/3$ |
