Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Indefinite Integration

Question:

Find the integral \(\int\frac{( { x }^{ 2 } - 1)}{x+1}dx\)

Options:

\[\frac{ { x }^{ 2} }{2} - x +c\]

\[\frac{ { x }^{ 2 } }{-2} - x +c\]

\[\frac{- { x }^{ 2 } }{2} - x +c\]

\[\frac{ { x }^{ 2 } }{2} + x +c\]

Correct Answer:

\[\frac{ { x }^{ 2} }{2} - x +c\]

Explanation:

\[\int x dx = \frac{ { x }^{ 2 } }{2}+c\]