CUET Preparation Today
CUET
General Test
Quantitative Reasoning
Algebra
If x2−2√5x+1=0, then what is the value of x5+1x5? |
612√5 408√5 610√5 406√5 |
610√5 |
If x2−2√5x+1=0, then what is the value of x5+1x5 = ? x5 + 1x5 = (x2 + 1x2) × (x3 + 1x3) – (x + 1x) If K+1K=n then, K2+1K2 = n2 – 2 If x + 1x = n then, x3+1x3 = n3 - 3 × n If x2−2√5x+1=0, then, divide equation by x on both sides, x + 1x = 2√5 x3+1x3 = ( 2√5)3 - 3 × 2√5 = 34√5 x2+1x2 = (2√5)2 – 2 = 18 x5 + 1x5 = 18 × 34√5 - 2√5 x5 + 1x5 = 612√5 - 2√5 = 610√5 |