Calculate the adjacent sides of a rectangle with a given perimeter as 100 cm and enclosing the maximum area. |
$x = 30\text{ cm}, y = 20\text{ cm}$ $x = 25\text{ cm}, y = 25\text{ cm}$ $x = 40\text{ cm}, y = 10\text{ cm}$ $x = 35\text{ cm}, y = 15\text{ cm}$ |
$x = 25\text{ cm}, y = 25\text{ cm}$ |
The correct answer is Option (2) → $x = 25\text{ cm}, y = 25\text{ cm}$ ## Let $x$ and $y$ be the adjacent sides of the rectangle, $∴2x + 2y = 100 \Rightarrow x + y = 50 \dots(i)$ Let $A$ be the area of rectangle. $∴A = xy$ Using (i), we get $A = x(50 - x)$ $\Rightarrow A = 50x - x^2$ $∴\frac{dA}{dx} = 50 - 2x$ For maximum area $\frac{dA}{dx} = 0 \Rightarrow 50 - 2x = 0$ $\Rightarrow x = 25$ When $x = 25, y = 50 - 25 = 25$ Hence, adjacent sides are $x = 25 \text{ cm}$ and $y = 25 \text{ cm}$. |