If $x + \frac{1}{x} = -13$, what is the value of $x^4 +\frac{1}{x^4}$ ?
Answer & explanation
Correct answer: option 1
We know that,
If $K+\frac{1}{K}=n$
then, $K^2+\frac{1}{K^2}$ = n2 – 2
So,
If $x + \frac{1}{x} = -13$,
= $x^2 +\frac{1}{x^2}$ = 132 – 2 = 167
The value of $x^4 +\frac{1}{x^4}$ = 1672 – 2 = 27887