If $x + \frac{1}{x} = -13$, what is the value of $x^4 +\frac{1}{x^4}$ ? |
27887 27891 29243 28561 |
27887 |
We know that, If $K+\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 – 2 So, If $x + \frac{1}{x} = -13$, = $x^2 +\frac{1}{x^2}$ = 132 – 2 = 167 The value of $x^4 +\frac{1}{x^4}$ = 1672 – 2 = 27887 |