Practicing Success
Practicing Success
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If $y=\sin^{-1}(\cos x)+\cos^{-1}(\sin x),0<x<\frac{π}{2}$, then $\frac{dy}{dx}$ is: |
-2 2 1 0 |
-2 |
$y=\sin^{-1}(\cos x)+\cos^{-1}(\sin x)=(\frac{π}{2}-x)+(\frac{π}{2}-x)=π-2x$ $\frac{dy}{dx}=-2$ |
