CUET Preparation Today
CUET
-- Mathematics - Section A
Continuity and Differentiability
If $y=\sin^{-1}(\cos x)+\cos^{-1}(\sin x),0<x<\frac{π}{2}$, then $\frac{dy}{dx}$ is:
-2
2
1
0
$y=\sin^{-1}(\cos x)+\cos^{-1}(\sin x)=(\frac{π}{2}-x)+(\frac{π}{2}-x)=π-2x$
$\frac{dy}{dx}=-2$
