The value of $tan^{-1}\frac{1}{2}+tan^{-

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The value of $tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}$ , is

Options:

$\frac{\pi}{3}$

$\frac{\pi}{6}$

$\frac{\pi}{4}$

Correct Answer:

$\frac{\pi}{4}$

Explanation:

We have

$tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}= tan^{-1}\left(\frac{1/2+1/3}{1-1/2×1/3}\right) = tan^{-1}1=\frac{\pi}{4}$