The value of $tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}$, is
Answer & explanation
Correct answer: option 4
We have
$tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}= tan^{-1}\left(\frac{1/2+1/3}{1-1/2×1/3}\right) = tan^{-1}1=\frac{\pi}{4}$
The value of $tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}$, is
Correct answer: option 4
We have
$tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}= tan^{-1}\left(\frac{1/2+1/3}{1-1/2×1/3}\right) = tan^{-1}1=\frac{\pi}{4}$