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The value of $tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}$, is |
0 $\frac{\pi}{3}$ $\frac{\pi}{6}$ $\frac{\pi}{4}$ |
$\frac{\pi}{4}$ |
We have $tan^{-1}\frac{1}{2}+tan^{-1}\frac{1}{3}= tan^{-1}\left(\frac{1/2+1/3}{1-1/2×1/3}\right) = tan^{-1}1=\frac{\pi}{4}$ |
