Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The velocity with which an object should be projected from the surface of the earth such that it reaches a maximum height equal to “n” time the radius of earth “R” is : (M = Mass of the earth)

Options:

[((n+1)*G*M)/(n+1)R]2

[(n*G*M)/(n+1)R] d) [((n+1)*G*M)/nR]2

[(n*G*M)/(n+1)R]1/2

none of these

Correct Answer:

[(n*G*M)/(n+1)R]1/2

Explanation:

Total initial energy = Total final energy

1/2(m x v2) – (G*M*m)/R = -(G*M*m)/(n+1)R

Simplifying the above equation, we get ;

v = [(n*G*M)/(n+1)R]1/2.