Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

$\underset{x→0}{\lim}\begin{Bmatrix}\tan\begin{pmatrix}\frac{π}{4}-x\end{pmatrix}\end{Bmatrix}^{1/x}$ is equal to

Options:

1

$e$

$e^2$

$e^{-2}$

Correct Answer:

$e^{-2}$

Explanation:

Limit = $e^{\underset{x→0}{\lim}\frac{1}{x}\log\begin{Bmatrix}\tan\begin{pmatrix}\frac{π}{4}-x\end{pmatrix}\end{Bmatrix}}=e^{\underset{x→0}{\lim}\frac{\cot\begin{pmatrix}\frac{π}{4}-x\end{pmatrix}.\sec^2\begin{pmatrix}\frac{π}{4}-x\end{pmatrix}.(-1)}{1}}=e^{-2}$