Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Average

Question:

A is the average marks of a group of 10 students in a class and A+8 is the average of a group of 15 students which includes the group of 10 students as given. The total marks obtained by the group of 10 students is X and the total marks obtained by the group of 15 students is Y. If X : Y = 3 : 5, then the value of A+X+Y is _________.

Options:

1964

1845

2012

1992

Correct Answer:

1992

Explanation:

Sum of marks of 10 students = 10A

Sum of marks of 15 students = 15 × ( A + 8) = 15A + 120

ATQ ,

\(\frac{10A}{15A + 120}\) = \(\frac{3}{5}\)

45A + 360 = 50A

5A = 360 ⇒ A = 72

SO , A + X + Y = 72 + 720 + 1080 +  120 = 1992