An observer 1.6 m tall is $20 \sqrt{3} ~m$ away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of tower is:

21.6 m

observer is1.6 m tall is 20√3 m away from a tower

angle of elevation from his eye to the top of the tower = 30°

\(\tan {30°}\) = (Height of tower-Height of observer)/20√3

1/√3 * 20√3 = Height of tower - 1.6

Height of tower= 20+1.6 

The correct answer is Option (1) → 21.6 m