An observer 1.6 m tall is $20 \sqrt{3} ~m$ away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of tower is:
Answer & explanation
Correct answer: option 1
observer is1.6 m tall is 20√3 m away from a tower
angle of elevation from his eye to the top of the tower = 30°
\(\tan {30°}\) = (Height of tower-Height of observer)/20√3
1/√3 * 20√3 = Height of tower - 1.6
Height of tower= 20+1.6
The correct answer is Option (1) → 21.6 m