$∫\frac{1-sinx}{cos^2x}dx$ is equal

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

$∫\frac{1-sinx}{cos^2x}dx$ is equal to :

Options:

$tanx-secx+C$ Where C is the constant of integration

$cotx-cosecx+C$ Where C is the constant of integration

$tanx+secx+C$ Where C is the constant of integration

$cotx+cosecx+C$ Where C is the constant of integration

Correct Answer:

$tanx-secx+C$ Where C is the constant of integration