What is the value of x, if $5(1-\frac{x}{5})- (5- x) - \frac{1}{200}$ of (20 –x) = 0.08 ?

36

$5(1-\frac{x}{5})- (5- x) - \frac{1}{200}$ of (20 –x) = 0.08 

= 5 (1 - \(\frac{x}{5}\)) - (5 - x) - \(\frac{1}{10}\) + \(\frac{x}{200}\) = \(\frac{8}{100}\)

= 5 - x - 5 + x - \(\frac{1}{10}\) + \(\frac{x}{200}\) = \(\frac{8}{100}\)

= \(\frac{x}{200}\) - \(\frac{1}{10}\)= \(\frac{8}{100}\)

= \(\frac{x}{200}\) = \(\frac{8}{100}\) + \(\frac{1}{10}\)

= \(\frac{x}{200}\) = \(\frac{18}{100}\)

= \(\frac{x}{2}\) = 18

= x = 2 × 18 = 36