A charge q is enclosed by a Gaussian spherical surface of radius R. If the radius is reduced to half of R, the outward electric flux will be |
reduced to half of its initial value the same as its initial value twice its initial value four times its initial value |
the same as its initial value |
The correct answer is Option (2) → the same as its initial value According to Gauss's law: $\Phi_E = \frac{q_\text{enclosed}}{\epsilon_0}$ The electric flux depends only on the total charge enclosed and not on the radius of the Gaussian surface. ∴ Reducing the radius to half, the outward electric flux remains the same |