If tan θ + cot θ = 8, then what is the value of tan2 θ + cot2 θ ?
Answer & explanation
Correct answer: option 3
We are given that :-
tan θ + cot θ = 8
On squaring both side,
( tan θ + cot θ )² = 8²
tan² θ + cot² θ + 2 tan θ . cot θ = 64
tan² θ + cot² θ + 2 = 64 { tan θ = \(\frac{1}{cotθ}\) }
tan² θ + cot² θ = 62