Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

The value of $\frac{cos8°cos24°cos60°cos66°cos82°}{sin82°sin66°sin60°sin8°sin24°}$ is :

Options:

1

$\frac{1}{\sqrt{2}}$

$\frac{1}{\sqrt{3}}$

0

Correct Answer:

$\frac{1}{\sqrt{3}}$

Explanation:

$\frac{cos8°cos24°cos60°cos66°cos82°}{sin82°sin66°sin60°sin8°sin24°}$

Using ,

cos θ = sin ( 90º - θ)

=  $\frac{cos(90°-82°)cos(90°-66°)cos60°cos(90°-24°)°cos(90°-8°)}{sin82°sin66°sin60°sin8°sin24°}$

=  $\frac{sin8°sin24°cos60°sin66°sin82°}{sin82°sin66°sin60°sin8°sin24°}$

=  $\frac{cos60°}{sin60°}$

= cot60°

= \(\frac{1}{√3}\)