If sin θ = \(\frac{3}{11}\), then what is the value of cotθ ?

$\frac{3\sqrt{7}}{11}$ $\frac{4\sqrt{7}}{11}$ $\frac{4\sqrt{7}}{3}$ $\frac{3\sqrt{7}}{28}$

$\frac{4\sqrt{7}}{3}$

We are given that , sinθ = \(\frac{3}{11}\) { we know, sinA = \(\frac{P}{H}\) } By using pythagoras theorem, P² + B² = H² 3² + B² = 11² B²  = 121 - 9 = 112 B = 4√7 Now, cotθ = \(\frac{B}{P}\) = \(\frac{4√7}{3}\)