Practicing Success
Practicing Success
CUET Preparation Today
What is the expression of $(2 + \frac{1}{p})^2$ ? |
$4 +\frac{4}{p}+\frac{1}{p^2}$ $2 +\frac{2}{p}+\frac{1}{p^2}$ $2 +\frac{4}{p}+\frac{1}{p^2}$ $4 +\frac{2}{p}+\frac{1}{p^2}$ |
$4 +\frac{4}{p}+\frac{1}{p^2}$ |
( a + b )2 = a2 + b2 + 2ab $(2 + \frac{1}{p})^2$ $(2 + \frac{1}{p})^2$ = 22 + \(\frac{1}{p^2}\) + 2 × 2 × \(\frac{1}{p}\) $(2 + \frac{1}{p})^2$ = $4 +\frac{4}{p}+\frac{1}{p^2}$ |
