Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The ratio of the dimensions of Planck's constant and that of moment of inertia is the dimensions of

Options:

Time

Frequency

Angular Momentum

Velocity

Correct Answer:

Frequency

Explanation:

Plank constant (h) = p${\lambda}$= $[MLT^{-1}]$[L] = $[ML^2T^{-1}]$

Moment of Inertia I = ${mr^2}$ = $[ML^2]$

ratio $\frac{h}{I}$ = $\frac{[ML^2T^{-1}]}{[ML^2T^{-1}]}$ = $[T^{-1}]$ = Frequency