The ratio of the dimensions of Planck's constant and that of moment of inertia is the dimensions of
Answer & explanation
Correct answer: option 2
Plank constant (h) = p${\lambda}$= $[MLT^{-1}]$[L] = $[ML^2T^{-1}]$
Moment of Inertia I = ${mr^2}$ = $[ML^2]$
ratio $\frac{h}{I}$ = $\frac{[ML^2T^{-1}]}{[ML^2T^{-1}]}$ = $[T^{-1}]$ = Frequency