CUET Preparation Today
If (x - \(\frac{1}{3}\))2 + (y - 4)2 = 0, then find the value of \(\frac{y + x}{y - x}\). |
\(\frac{11}{12}\) \(\frac{12}{11}\) \(\frac{11}{13}\) \(\frac{13}{11}\) |
\(\frac{13}{11}\) |
Formula → If (x - a)2 + (y - b)2 = 0, then x = a and y = b Applying the concept → x = \(\frac{1}{3}\) y = 4 put in equation, \(\frac{y + x}{y - x}\) = \(\frac{4 + \frac{1}{3}}{4 - \frac{1}{3}}\) = \(\frac{13}{11}\) |
