Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Which of the following functions is differentiable at x = 0?

Options:

$e^{|x|}+|x|^2$

$e^{|x|}-|x|^2$

$\tan(|x|)+|x|$

$\tan(|x|)-|x|$

Correct Answer:

$\tan(|x|)-|x|$

Explanation:

Linear combination of one differentiable and one non-differentiable function is always nondifferentiable.

Hence (a) and (b) are wrong.

Now, $\tan(|x|)-|x|=\frac{|x|^3}{3}+\frac{2|x|^5}{15}+.....$ is differentiable at x = 0,

whereas $\tan(|x|)+|x|=2|x|+\frac{|x|^3}{3}+\frac{2|x|^5}{15}+.....$ is not differentiable at x = 0.

[∵ |x| is not diff. at x = 0]