The general solution of the differential equation $\frac{dy}{dx}+4x\, y^2 =0 $ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $y=\frac{1}{2x^2-C}, $ where C is a constant
$\frac{dy}{dx}=-4xy^2⇒\int\frac{1}{y^2}dy=\int-4xdx$
$⇒-\frac{1}{y}=-2x^2+C$
So $y=\frac{1}{2x^2-C}$