What is the average power dissipated in

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Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

What is the average power dissipated in a resistive circuit? (I_m is the peak value of current and I is the instantaneous current.)

Options:

I²R/2

I_m²R/2

I²R/\(\sqrt { 2}\)

I_m²R/\(\sqrt { 2}\)

Correct Answer:

I_m²R/2

Explanation:

Instantaneous power : P = I²R = I_m²R sin²wt

Average power : <P> = I_m²R sin²wt = I_m²R <sin²wt> = \(\frac{I_m²R}{2}\)