What is the average power dissipated in a resistive circuit? (Im is the peak value of current and I is the instantaneous current.)
Answer & explanation
Correct answer: option 2
Instantaneous power : P = I2R = Im2R sin2wt
Average power : <P> = Im2R sin2wt = Im2R <sin2wt> = \(\frac{Im2R}{2}\)