CUET Preparation Today
An electromagnetic wave going through vacuum is described by $E=E_0 \sin (k x-\omega t) ; B = B_0 \sin (k x-\omega t)$. Then, |
$E_0 k=B_0 \omega$ $E_0 B_0=\omega k$ $E_0 \omega=B_0 k$ None of these |
$E_0 k=B_0 \omega$ |
$\frac{E_0}{B_0}=\frac{\omega}{k}$ or $E_0 k=B_0 \omega$ |
