A parallel plate capacitor is charged to 60 µC. Due to a radioactive source, the plate losses charge at the rate of 1.8 × 10-8 Cs-1. The magnitude of displacement current is:
Answer & explanation
Correct answer: option 1
Displacement current is given by $I_{D}=\frac{dq}{dt}=1.8 \times 10^{-8} Cs^{-1}$