A parallel plate capacitor is charged to 60 µC. Due to a radioactive source, the plate losses charge at the rate of 1.8 × 10-8 Cs-1. The magnitude of displacement current is:

1.8 × 10-8 Cs-1 3.6 × 10-8 Cs-1 4.1 × 10-11 Cs-1 5.7 × 10-12 Cs-1

1.8 × 10-8 Cs-1

Displacement current is given by $I_{D}=\frac{dq}{dt}=1.8 \times 10^{-8} Cs^{-1}$