A reaction is first order in A and second order in B. How is rate affected when concentration of B is tripled?

Rate increases by nine times Rate decreases by nine times Rate increases by three times Rate decreases by three times

Rate increases by nine times

rate = K [A]1 [B]2 (ii) Rate, r1 = K [A]1[B]2 …………… (i) When concentration of B is increased three times then Rate, r2 = K [A]1 [3B]2 ………..(ii) Dividing equation (ii) by (i) we get r2 = 9r1 rate increases by nine times.