A reaction is first order in A and second order in B. How is rate affected when concentration of B is tripled?
Answer & explanation
Correct answer: option 1
rate = K [A]1 [B]2
(ii) Rate, r1 = K [A]1[B]2 …………… (i)
When concentration of B is increased three times then
Rate, r2 = K [A]1 [3B]2 ………..(ii)
Dividing equation (ii) by (i) we get
r2 = 9r1 rate increases by nine times.