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CUET
General Test
Quantitative Reasoning
Trigonometry
Solve \(\frac{tan71°-tan19°-2tan38°}{tan14°}\)
4
6
2
1
⇒ \(\frac{tan71°-tan19°-2tan38°}{tan14°}\)
⇒ \(\frac{tan(71°-19°)-2tan38°}{tan14°}\)
⇒ \(\frac{2tan52°-2tan38°}{tan14°}\)
⇒ \(\frac{2tan14°}{tan14°}\)
= 2